Question

The sum of two rational numbers is -3. If one of the them is $-\frac{10}{3}$ then the other one is

(a) $\frac{-13}{3}$

(b) $\frac{-19}{3}$

(c) $\frac{1}{3}$

(d) $\frac{13}{3}$

Answer 1

Sum = -3, one number = $\frac{-10}{3}$

$\therefore$ Second number = $-3-\left(\frac{-10}{3}\right)$

$=-3+\frac{10}{3}=\frac{-9+10}{3}=\frac{1}{3}$