The sum of two +ve numbers is 20. If the sum of their square is minimum then one of the number is

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Solution

The correct option is D $10$
$x + y = 20$
$S u m = x^{2} + y^{2}$
$\frac{d (S u m)}{d x} = 2 x + 2 (20 - x) (- 1)$
$0 = x - 20 + x$
$x = 10$

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