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Higher Order Derivatives

The sum of x ...

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The sum of x and y intercepts cut off by the circle x^2+y^2+4x-8y-2=0 is:

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Q. Find length of intercept cut off by well

x^{2} + y^{2} + 4 x - 2 y - 3 = 0

x - y + 2 = 0

x^{2} + y^{2} = 1

x^{2} + y^{2} - 4 x - 6 y + 12 = 0

cut off equal intercepts on a line through the point

(1, 1)

. The slope of the line is

Q. The equation of the circle passing through the origin which cuts off intercept of length 6 and 8 from the axes is
(a) x² + y² − 12x − 16y = 0
(b) x² + y² + 12x + 16y = 0
(c) x² + y² + 6x + 8y = 0
(d) x² + y² − 6x − 8y = 0

x^{2} + y^{2} + 4 x - 7 y + 12 = 0

cuts an intercept on y-axis is equal to

Q. The length of the

y

-intercept made by the circle

x^{2} + y^{2} - 4 x - 6 y - 5 = 0

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