The supplement angle of the complement of $30^{o}$ is

150^{o}

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120^{o}

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90^{o}

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210^{o}

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Solution

The correct option is B $120^{o}$
Complement of $30^{o} = 60^{o}$
Supplement of $60^{o} = 120^{o}$

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Similar questions

∠ A

30^{o}

∠ B

120^{o}

(90^{o} - y)

Find the angle whose complement is one third of its supplement.

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