The surface area of the base of a brick X kept on a surface is 100 $c m^{2}$ and that of the brick Y is 250 $c m^{2} .$ If each brick weighs 100 N, which of the following is correct if $P_{1}$ and $P_{2}$ are the pressures exerted by bricks X and Y respectively?

P_{1} = P_{2}

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P_{1} < P_{2}

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P_{1} > P_{2}

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P_{1} = P_{2} = 0

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Solution

The correct option is C $P_{1} > P_{2}$
Pressure exerted by the brick X is given by,
$P_{1} = \frac{Weight of the brick}{Surface area of the base} = \frac{100 N}{100 c m^{2}} = 1 N c m^{- 2}$ Pressure exerted by the brick Y is given by,
$P_{2} = \frac{Weight of the brick}{Surface area of the base} = \frac{100 N}{250 c m^{2}} = 0.4 N c m^{- 2}$

So, $P_{1} > P_{2}$

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The surface area of the base of a brick X kept on a surface is 100 cm2 and that of the brick Y is 250 cm2. If each brick weighs 100 N, which of the following is correct if P1 and P2 are the pressures exerted by bricks X and Y respectively?

The correct option is C P1>P2Pressure exerted by the brick X is given by, P1=Weight of the brickSurface area of the base=100 N100 cm2=1 N cm−2 Pressure exerted by the brick Y is given by, P2=Weight of the brickSurface area of the base=100 N250 cm2=0.4 N cm−2 So, P1>P2

The surface area of the base of a brick X kept on a surface is 100 $c m^{2}$ and that of the brick Y is 250 $c m^{2} .$ If each brick weighs 100 N, which of the following is correct if $P_{1}$ and $P_{2}$ are the pressures exerted by bricks X and Y respectively?