The tangent to the curve y - x 3-1 at 1-2 makes an angle - with y axis- then the value of tan- isA- -3B- -1 - 4C- 4D- 1 - 3

The correct option is D 1/3 Slope = tan x = 3 ⇒ cot x =1/3 ⇒ tan θ = 1/3 ...

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Parametric Differentiation

The tangent t...

Question

The tangent to the curve $y = x^{3} + 1$ at (1, 2) makes an angle $θ$ with y axis, then the value of tan $θ$ is

-1/4

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-3

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1/3

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Solution

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y = x^{3} + 1

θ

θ

y = x^{2}

y = x^{3}

θ

tan θ = m

∣ ∣ \frac{1}{m} ∣ ∣

y = x^{7} + 8 x^{3} + 2 x + 1

y = a_{0} x^{2 n - 1} + a_{1} x^{2 n - 1} + a_{2} x^{2 n - 3} + . . . . . . . a_{n} x + 1

a_{1}, . . . . . . . . a_{n - 1} \geq 0; a_{0} > 0

n \in N

x^{3} - y^{2} = 0

(m^{2}, - m^{3})

= - \frac{1}{m} x - 2 m^{3},

m^{2}

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