Question

The temperature at which numerical value of the Celsius reading is half that of the Fahrenheit reading

• A. ${40}^{\circ }C$
• B. ${20}^{\circ }C$
• C. ${160}^{\circ }C$
• D. ${80}^{\circ }C$

Answer 1

Answer: (C)

${160}^{\circ }C$

$\frac{2x-32}{180}=\frac{x}{100}$
$0.2x=32$
$\Rightarrow x={160}^{o}C$