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Question

The temperature at which the r.m.s. speed of O2 is equal to that of neon at 300 K is:
(atomic mass of O2 = 32 u and Ne = 20 u)

A
280 K
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B
480 K
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C
680 K
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D
180 K
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Solution

The correct option is B 480 K
rms velocity TM
where, T is the temperature and M is the molar mass.
Given,
rms velocity of oxygen at T K=rms velocity of neon at 300 K
T32×103=30020×103

u1u2=T1×M2T2M1

Hence, T=480 K

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