The temperature co-efficient of resistance of a wire is 0.0012/∘C. Its resistance is 1Ω at 300K. At what temperature, its resistance will be 2Ω?
A
1133K
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B
854K
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C
1217K
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D
1154K
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Solution
The correct option is D1133K Given : α=0.0012/oCR300=1ΩT1=300KR′=2Ω Resistance at a temperature is given by R′=R300(1+αΔT) ∴2=1(1+0.0012×ΔT) Or ΔT=T′−300=833.33 ⟹T′=833+300=1133K