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Question

The temperature coefficient of resistance of a wire is 0.00125/C. Its resistance is 1Ω at 300 K. Its resistance will be 2 Ω at:

A
1127 K
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B
1400 K
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C
1154 K
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D
1100 K
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Solution

The correct option is A 1127 K
Given : α=0.00125/oC
Using RT=R273(1+α(T273))
For T=300, R300=1Ω
R300=R273(1+α(300273))
OR 1=R273(1+0.00125(300273)) R273=0.967Ω

Let at temperature be T when RT=2Ω
RT=R273(1+α(T273))
OR 2=0.967(1+0.00125(T273))
OR T273=854.6
T=273+854.6=1127.6K

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