The temperature gradient of 0.5m long rod is 80oC/m. If the temperature of hotter end of the rod is 30oC, then the temperature of the cooler end is
A
40oC
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B
−10oC
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C
10oC
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D
0oC
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Solution
The correct option is B−10oC Temperature gradient m =80C/m Temperature of hotter end Th=30C Let temperature of cooler end be Tc Length of rod is l=0.5 m m=80=Th−Tcl Tc=−10C