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Question

The temperature inside a refrigerator is t 2°C and the room temperature is t 1°C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

A
t2+273t1t2
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B
t1+t2t1+273
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C
t1t1t2
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D
t1+273t1t2
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Solution

The correct option is D t1+273t1t2
Coefficient of Performance of Refrigerator
COP=QcW=t2+273t1t2

We have to find heat given to room per unit electrical energy.
Room is at higher temperature and act as hot reservoir. And electrical energy is the input energy shown as W.

So, we have to find QHW

Again, QH=Qc+W

QHW=QcW+1

=t2+273t1t2+1

QHW=t1+273t1t2

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