The temperature of 20 litre of nitrogen was increased from 100 K to 300 K at a constant pressure. The change in volume will be:

80 litres

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60 litres

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40 litres

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20 litres

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Solution

The correct option is D 40 litres
The temperature of $20$ litre was increased from $100$ K to $300$ K at constant pressure. So, $V_{1} = 20$ litre, $T_{1} = 100$ K and $T_{2} = 300$ K at constant pressure,
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$\Rightarrow \frac{20}{100} = \frac{V_{2}}{300} \Rightarrow V_{2} = 60$ litre
$∴$ Change in volume will be $(60 - 20)$ lit i.e. $40$ lit.
$∴$ Correct answer is C.

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The temperature of 20 litre of nitrogen was increased from 100 K to 300 K at a constant pressure. The change in volume will be:

The correct option is D 40 litresThe temperature of 20 litre was increased from 100K to 300K at constant pressure. So, V1=20 litre, T1=100K and T2=300K at constant pressure,V1T1=V2T2⇒20100=V2300⇒V2=60 litre∴ Change in volume will be (60−20) lit i.e. 40 lit.∴ Correct answer is C.