The temperature of $20$ litres of nitrogen was increased from $100 K$ to $300 K$ at a constant pressure. Change in volume will be

80

litres

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60

litres

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40

litres

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20

litres

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Solution

The correct option is C $40$ litres
Given
$T_{1} = 100$
$T_{2} = 300 K$
$V_{1} = 20 l$
We know that,

$\frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}}$

$\frac{20}{V_{2}} = \frac{100}{300}$

$V_{2} = 60 l i t r e s$

Change in volume will be (60−20) lit i.e. 40 lit.

Hence, option C is correct.

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The temperature of 20 litres of nitrogen was increased from 100 K to 300 K at a constant pressure. Change in volume will be

The correct option is C 40 litresGivenT1=100T2=300KV1=20lWe know that,V1V2=T1T220V2=100300V2=60litresChange in volume will be (60−20) lit i.e. 40 lit.Hence, option C is correct.

The temperature of $20$ litres of nitrogen was increased from $100 K$ to $300 K$ at a constant pressure. Change in volume will be

The correct option is C $40$ litres
Given
$T_{1} = 100$
$T_{2} = 300 K$
$V_{1} = 20 l$
We know that,

$\frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}}$

$\frac{20}{V_{2}} = \frac{100}{300}$

$V_{2} = 60 l i t r e s$

Change in volume will be (60−20) lit i.e. 40 lit.

Hence, option C is correct.