Question

The temperature of a gas is T K. What would be the temperature at which volume and pressure, both will reduce to half of the initial values?

• A. T/2
• B. T/4
• C. T/3
• D. T/8

Answer 1

The correct option is B T/4

Given that,

$P_1=P,T_1=T,V_1=V$

$P_2=\frac{P}{2},V_2=\frac{V}{2},T_2=?$

By using $\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$\frac{P\times V}{T}=\frac{P\times V}{2\times 2\times T_2}$

$\Rightarrow T_2=\frac{T}{4}$

Hence, option B is correct.