Question

The temperature of an ideal gas at atmospheric pressure is 300K and volume $l{m}^3$.If temperature and volume become double, then pressure will be

• A. ${10}^{5}N/m^2$
• B. $2\times {10}^{5}N/m^2$
• C. $0.5\times {10}^{5}N/m^2$
• D. $4\times {10}^{5}N/m^2$

Answer 1

The correct option is A ${10}^{5}N/m^2$

$\begin{array}{c}\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}\\ \Rightarrow \frac{{10}^5\times \left(1m^3\right)}{300K}=\frac{P\left(2\right)}{600}\\ \Rightarrow P={10}^{5}N/m^2\\ Hence,\\ optionAiscorrectanswer.\end{array}$