The temperature of inversion of a thermocouple is 700oC and the neutral temperature is 365oC. Then the temperature of cold function must be
A
0oC
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B
300C
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C
35oC
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D
65oC
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Solution
The correct option is B300C Given:ti=700oC ; tn=365oC
Solution: As we know the temperature of inversion is higher than the neutral temperature by the same amount as the neutral temperature is higher than the temperature of cold junction. Hence, tn−t0=ti−tn⇒t0=2tn−ti