The ten's place of a two digit number is three times the unit digit .The sum of the number and the unit digit is 32 .Find the number.

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Solution

Let the tens digit be x and units digit be y.
So, the number is 10x+y. x=3y (given)...........(eq.1)
10x+y+y=32 (given)
Substituting the value of x from eq. 1,
10(3y)+y+y=32
30y+y+y=32
32y=32
y=1
So, x=3y=3×1=3
Hence , the number is 31

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The ten's place of a two digit number is three times the unit digit .The sum of the number and the unit digit is 32 .Find the number.

Let the tens digit be x and units digit be y. So, the number is 10x+y. x=3y (given)...........(eq.1) 10x+y+y=32 (given) Substituting the value of x from eq. 1, 10(3y)+y+y=32 30y+y+y=32 32y=32 y=1 So, x=3y=3×1=3 Hence , the number is 31

Let the tens digit be x and units digit be y.
So, the number is 10x+y. x=3y (given)...........(eq.1)
10x+y+y=32 (given)
Substituting the value of x from eq. 1,
10(3y)+y+y=32
30y+y+y=32
32y=32
y=1
So, x=3y=3×1=3
Hence , the number is 31