The tens digit of a two digit number is two times the ones digit. If you interchange the digits and add the resulting number to original number you get 66. Find the original number.
42
Let the ones digit of the number be x.
Then, the tens digit will be 2x.
So, the number will be (2x×10)+(x×1)=20x+x=21x
On interchanging the digits, the number will be (x×10)+(2x×1)=10x+2x=12x
It is given that 21x+12x=66
⇒33x=66
⇒x=6633
⇒x=2
Hence, ones digit of the number is 2 and tens digit is 4.
The original number is 42.