Question

The tension $T$ in the string in figure is

• A. Zero
• B. $50N$
• C. $35\sqrt{3}N$
• D. $(\sqrt{3}-1)50N$

Answer 1

The correct option is A Zero

Friction force is trying to uppose the motion so,
$f_s=\mu mg\cos {30}^0=0.7\times 10\times 10\times \frac{\sqrt{3}}{2}$
$f_s=35\sqrt{3}=60.62N$
Gravitational force helping in motion i.e,
$F=mg\sin {30}^0=10\times 10\times \frac{1}{2}=50N$
Since $f_s>F$, this means friction force is sufficient to oppose gravitational force. So, tension will be Zero