Question

The $\text{N-N}$ bond length is expected to be highest in which of the following compounds gaseous form?

• A. ${\text{N}}_{\text{2}}\text{O}$
• B. ${\text{N}}_{\text{2}}{\text{O}}_5$
• C. ${\text{N}}_{\text{2}}{\text{O}}_3$
• D. ${\text{N}}_{\text{2}}{\text{H}}_{\text{4}}$

Answer 1

The correct option is A ${\text{N}}_{\text{2}}\text{O}$

$N_2{O}_5$ does not have $N-N$ bond in $N_2{O}_5$, O have -ve charge which is making it stable and also $O$ being more electronegative attracts the $e^{-}$ density towards itself making the adjacent $N_2,e^{-}$ deficient and weak. Thus $N-N$ bond is longer.