The thermal decomposition of N2O4g) ⇋ 2NO2 (g) is as shown below:
N2O4(g)⇌2NO2(g)At starta mol 0 molAt equb.(a−x)mol 2x mol
Where x = degree of dissociation. If V and P are equilibrium volume and pressure respectively then the corresponding expressions for Kc and Kp are 4x2V(a−x) and 4x2a2−x2 (respectively). True or False?
True
Calculating Kc:N2O4(g)⇌2NO2(g)At starta mol 0 molAt equb.(a−x)mol 2x mol
Kc=[2xV]2a−xV=4x2(a−x)V
Calculating Kp:N2O4(g)⇌2NO2(g)At starta mol 0 molAt equb.(a−x)mol 2x mol
Total number of moles at equilibrium=a−x+2x=a+x
At equilibrium,PNO2=2x+Pa+xPN2O4=(a−x)×P(a+x)∴Kp=(2x×Pa+x)2(a−x)×Pa+x=4x2×P(a−x)(a+x)=4x2Pa2−x2