The Thevenin equivalent impendance Z $_{T h}$ between the nodes P and Q in the following circuit is

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1 + s + \frac{1}{s}

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2 + s + \frac{1}{s}

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\frac{S^{2} + S + 1}{S^{2} + 2 s + 1}

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Solution

The correct option is A 1

$Z_{T h} = (s + 1) | | (1 + \frac{1}{s})$

$= \frac{(s + 1) (1 + \frac{1}{s})}{(s + 1) + 1 + \frac{1}{s}}$

$= \frac{(s + 1)^{2} / s}{(s + 1) (s + 1) / s} = 1$

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The Thevenin equivalent impendance ZTh between the nodes P and Q in the following circuit is

The correct option is A 1 ZTh=(s+1)||(1+1s) =(s+1)(1+1s)(s+1)+1+1s =(s+1)2/s(s+1)(s+1)/s=1

The Thevenin equivalent impendance Z $_{T h}$ between the nodes P and Q in the following circuit is

The correct option is A 1

$Z_{T h} = (s + 1) | | (1 + \frac{1}{s})$

$= \frac{(s + 1) (1 + \frac{1}{s})}{(s + 1) + 1 + \frac{1}{s}}$

$= \frac{(s + 1)^{2} / s}{(s + 1) (s + 1) / s} = 1$