Question

The thickness of a hemispherical bowl is $0.25$ cm. The inner radius of the bowl is $5$ cm. Find the outer curved surface area of the bowl. $(Take\pi =\frac{22}{7})$

Answer 1

Let $r-$ inner radius,
$R-$ outer radius
and $w-$ width
Given, $r=5$ cm, $w=0.25$ cm
We know, $R=r+w=5+0.25=5.25$ cm
The outer curved surface area $=2\pi R^2$ sq. cm. of bowl $=2\times \frac{22}{7}\times 5.25\times 5.25$
$=173.25c{m}^2$