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Question

The three resistance of equal value are arranged in the different combinations shown below.
Arrange them in increasing order of power dissipation.

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A
|||<||<|V<|
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B
||<|||<|V<|
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C
|<|V< III < II
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D
|<|||<||< IV
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Solution

The correct option is A |||<||<|V<|
Let each resistance =R

For I: P1=i2Req=i2(R+R+R)=i2(3R)

For II: P2=i2Req=i2×R(R+R)R+(R+R)=i2(2R/3)

For III: P3=i2Req=i2(R/3)

For IV: P4=i2Req=i2×(R/2+R)=i2(3R/2)

Thus, P3<P2<P4<P1

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