wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The thrust developed by a rocket motor is given by F=mv+A(P1P2) where m is the mass, v is the velocity of gas and A is area of cross section of the nozzle. P1,P2 are pressures of the exhaust gas and surrounding atmosphere. Then this equation is:

A
dimensionally correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
dimensionally wrong
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
some times correct and some times wrong
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
algebrically correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D dimensionally wrong
F=mv+A(P1P2)
Now, [F]=[M1L1T2]

and, [mv]=[M1L1T1]

Also, [A(P1P2)]=[L2×(M1L1T2) =[M1L1T2]

The two terms on the RHS of the equation have different dimensions and hence cannot be equated to the term on LHS.

[mv][F]=[A(P1P2)],

The equation is dimensionally wrong.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon