The time period of a simple pendulum is independent of

Acceleration of the frame of reference

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Velocity of the frame of reference

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Length of the string

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Solution

The correct option is B Velocity of the frame of reference
The time period of the pendulum in accelerted frame is given by :
$T = 2 π \sqrt{\frac{L}{a^{2} + g^{2}}}$

It is clear from the above relation that there is no dependency on velocity of the frame.

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The time period of a simple pendulum is independent of

The correct option is B Velocity of the frame of referenceThe time period of the pendulum in accelerted frame is given by : T=2π√La2+g2 It is clear from the above relation that there is no dependency on velocity of the frame.

The correct option is B Velocity of the frame of reference
The time period of the pendulum in accelerted frame is given by :
$T = 2 π \sqrt{\frac{L}{a^{2} + g^{2}}}$

It is clear from the above relation that there is no dependency on velocity of the frame.