Question

The time period of oscillation of a simple pendulum is $\sqrt{2}s$, If its length is decreased to half of initial length, then its new period is

• A. $1s$
• B. $0.707s$
• C. $0.414s$
• D. $0.5s$

Answer 1

Answer: (A)

$1s$

$T=2\pi \sqrt{\frac{l}{g}}=\sqrt{2}sec$
$L$ replaced by $\frac{l}{2}$
$T_1=\frac{T}{\sqrt{2}}=2\pi \sqrt{\frac{l}{2g}}=\frac{\sqrt{2}}{\sqrt{2}}=1sec$