The time period of oscillations is 0.5 s. L is 10 cm is known to have accuracy of 1mm. The time of 100 oscillations is measured with a wrist watch of 1s resolution .what is the accuracy in determination of g?

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The period of oscillation of a simple pendulum is $T = 2 π \sqrt{\frac{L}{g}}$ . Measure of $L$ is $20.0 c m$ known to $1 m m$ accuracy and time for $100$ oscillations of the pendulum is found to be $90 s$ using a wrist watch of $1 s$ resolution. The accuracy in the determination of $g$ ?

Q. The period of oscillation of a simple pendulum is T =

2 π \sqrt{\frac{L}{g}}

. Measured value of L is 10 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 50 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?

Q. The period of oscillation of a simple pendulum is

T = 2 π \sqrt{\frac{L}{g}}

. Measured value of

L

10 c m

known to

1 m m

accuracy and time for

100

oscillations of the pendulum is found to be

50 s

using a wristwatch of

1 s

resolution. What is the accuracy in the determination of

g

Q. The length of a simple pendulum is about

100 c m

, known to have an accuracy of

1 m m

. Its period of oscillation is

2 s

, determined by measuring the time for

100

oscillations using a clock of

0.1 s

resolution. What is the accuracy in the determined value of

g

The period of oscillation of a simple pendulum is $T = 2 π \sqrt{\frac{L}{g}}$ . Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillation of the pendulum is found to be 90 s using wrist watch of 1 s resolution. The accuracy in the determination of g is:

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