The time period of simple pendulum is T. If its length is increased by 2 the new time period becomes
A
0⋅99T
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B
1⋅01T
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C
1⋅02T
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D
0⋅98T
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Solution
The correct option is B1⋅01T As we know,
The time period of simple pendulum, T=2π√Lg
If it's length is increased by two 2% T′=2π√L(1+2/100)g T′T=(1+2100)12 =1+12⋅2100 =1⋅01 T′=1⋅01T
Final answer ; (d)