Question

The time taken by a body which is projected horizontally from a height '$h$' from the ground to reach the ground is................

• A. $\frac{g}{2h}$
• B. $\sqrt{\frac{g}{2h}}$
• C. $\frac{2h}{g}$
• D. $\sqrt{\frac{2h}{g}}$

Answer 1

The correct option is D $\sqrt{\frac{2h}{g}}$

When the particle is thrown horizontally from a height $h$, the particle will not have any vertical component of velocity. It falls down because of gravitational force. In the downward direction, the motion is the same as that of a dropped object.
So, $h=0+\frac{1}{2}g{t}^2$
Or, $t^2=2h/g$
Or, $t=\sqrt{2h/g}$