Question

The time taken by A.C. of $50Hz$ in reaching from zero to the maximum value is:

• A. $50\times {10}^{-3}s$
• B. $5\times {10}^{-3}s$
• C. $1\times {10}^{-3}s$
• D. $2\times {10}^{-3}s$

Answer 1

Answer: (B)

$5\times {10}^{-3}s$

$T=\frac{1}{f}=\frac{1}{50}=0.02s$

So, time required to reach from zero to maximum is quarter time period.

$\Rightarrow$ Time required $=\frac{T}{4}=\frac{0.02}{4}=0.005s$