Question

The time taken by a particle performing S.H.M. to pass from point $A$ to $B$ where its velocities are same is $2$ seconds. After another 2 seconds it returns to $B$ . The time period of oscillation is (in seconds):

• A. $2$
• B. $4$
• C. $6$
• D. $8$

Answer 1

The correct option is D $8$

According to the question, a and b points are such that they are

located at same distances from the equilibrium position.

Here also it is said that velocity is same

,i.e; not only the magnitude but also the directions are same.

So, total time period of oscillation $=2\times$( time taken to go from a to b

+ the next time taken to return at b) $=2\times (2+2)=8$ sec.