Question

The time taken for effusion of $64mL$ of oxygen will best as the time taken for the effusion of which of the following gases under identical conditions?

• A. $64mL$ of $H_2$
• B. $100mL$ of $N_2$
• C. $64mL$ of $C{O}_2$
• D. $45.24mL$ of $S{O}_2$

Answer 1

The correct option is D $45.24mL$ of $S{O}_2$

Using Graham's law of diffusion :

$\frac{r_{O_2}}{r_{gas}}=\sqrt{\frac{M_{gas}}{M_{O_2}}}$

$\frac{64}{V}=\sqrt{\frac{64}{32}}$ or $V=\frac{64}{\sqrt{2}}=45.25mL$.

Hence, the correct option is D.