The toll rates for crossing Bandra sea link are $$ 6.50$ for a two wheeler and $$ 10$ for a four wheeler. A total of $187$ vehicle crossed the bridge on a day and the total collected in tolls was $$ 1, 338$ . Which of the following system of equations will give $x$ the number of two wheelers and $y$ , the number of four wheeler on that particular day?

x + y = 1, 338 6.5 x + 10 y = 187

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x + y = 187 6.5 x + 10 y = \frac{1, 338}{2}

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x + y = 187 6.5 x + 10 y = 1, 338

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x + y = 187 6.5 x + 10 y == 1, 338 \times 2

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Solution

The correct option is C $x + y = 187 6.5 x + 10 y = 1, 338$
Given,
Toll rate for crossing Bandra sea link are 6.50 $f o r t w o w h e e l e r a n d$ $10$ for four wheeler.
Total vehicles that crossed bridge on a day $= 187$
Total cost collected in tolls $=$ 1338 $. W h e n w e a s s u m e$ x $b e t h e n u m b e r o f t w o w h e e l e r s a n d$ y $b e t h e n u m b e r o f f o u r w h e e l e r s, t h e n t o t a l n u m b e r o f v e h i c l e s t h a t c r o s s e d t h e b r i d g e w i l l b e,$ x+y=187 $T o t a l m o n e y c o l l e c t e d b y t w o w h e e l e r s w i l l b e$ 6.50\times x=6.50x $T o t a l m o n e y c o l l e c t e d b y f o u r w h e e l e r s w i l l b e$ 10\times y=10y $S o e q u a t i o n f o r t o t a l m o n e y c o l l e c t e d$ =6.50x+10y=1338 $H e n c e, t h e c o r r e c t s e t o f e q u a t i o n s a r e$ x+y=1876.50x+10y=1338$

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