The tops of two poles, of heights $25 m$ and $35 m$ are connected by a wire which makes an angle of elevation of $30^{\circ}$ at the top of $25 m$ pole. The length of wire (in m) is

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Solution

$sin 30^{0} = \frac{10}{l}$ $(\frac{o p p o s i t e s i d e}{h y p o t e n s e})$
$\frac{1}{2} = \frac{10}{l}$
$l = 20 m$
Length of wire is $20 m$

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The tops of two poles, of heights 25m and 35m are connected by a wire which makes an angle of elevation of 30∘ at the top of 25m pole. The length of wire (in m) is

sin300=10l (oppositesidehypotense)12=10ll=20mLength of wire is 20m

The tops of two poles, of heights $25 m$ and $35 m$ are connected by a wire which makes an angle of elevation of $30^{\circ}$ at the top of $25 m$ pole. The length of wire (in m) is

$sin 30^{0} = \frac{10}{l}$ $(\frac{o p p o s i t e s i d e}{h y p o t e n s e})$
$\frac{1}{2} = \frac{10}{l}$
$l = 20 m$
Length of wire is $20 m$