The torque applied to a ring revolving about its own axis so to charge its angular momentum by 2 j-s in 5 s,is

10 N-m

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2.5 N-m

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0.1-m

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0.4 N-m

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Solution

The correct option is D 0.4 N-m
$A c c o r d i n g t o q u e s t i o n . . . . . . . . . . . . . . . . . . . R e l a t i o n b / w T o r q u e (t) a n d a n g u l a r M o m e n t u m (L) i s g i v e n, [T o r q u e (t) = \frac{d L}{d t}] h e r e, d L = 2 J s d t = 5 s N o w, ∴ T o r q u e (t) = \frac{2}{5} = 0.4 N m s o t h e c o r r e c t o p t u o n i s D .$

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The torque applied to a ring revolving about its own axis so to charge its angular momentum by 2 j-s in 5 s,is

The correct option is D 0.4 N-mAccordingtoquestion...................Relationb/wTorque(t)andangularMomentum(L)isgiven,[Torque(t)=dLdt]here,dL=2Jsdt=5sNow,∴Torque(t)=25=0.4NmsothecorrectoptuonisD.