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Byju's Answer
Standard XII
Chemistry
Nernst Equation
The total cha...
Question
The total change in free energy during the cell reaction in
C
u
|
C
u
2
+
1
M
|
|
A
1
M
g
+
|
A
g
would be:
A
−
80.1
k
J
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B
−
40.05
k
J
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C
−
31.36
k
J
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D
−
62.72
k
J
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Solution
The correct option is
A
−
80.1
k
J
Given,
C
u
2
+
+
e
→
C
u
+
;
−
Δ
G
o
1
=
E
o
1
F
×
1
C
u
+
+
e
→
C
u
;
−
Δ
G
o
2
=
E
o
2
F
×
1
----------------------------
by adding these equations
C
u
2
+
+
2
e
→
C
u
;
−
Δ
G
o
3
=
−
[
Δ
G
o
1
+
Δ
G
o
2
]
=
−
[
0.15
F
+
0.5
F
]
or
2
×
E
o
3
F
=
0.65
F
(as
Δ
G
=
−
n
F
E
o
)
∴
E
o
3
=
0.325
V
So for reverse reaction.
∴
C
u
→
C
u
2
+
+
2
e
;
E
o
=
−
0.325
V
C
u
→
C
u
2
+
+
2
e
;
E
o
=
−
0.325
V
2
A
g
+
+
2
e
→
2
A
g
;
E
o
=
0.799
V
∴
E
o
c
e
l
l
=
E
o
O
P
C
u
/
C
u
2
+
+
E
o
R
P
A
g
+
/
A
g
=
−
0.325
+
0.799
=
0.474
V
Now according to Nernst equation:
E
=
E
o
−
0.0591
(
l
o
g
Q
)
/
n
E
c
e
l
l
=
E
o
c
e
l
l
+
0.059
2
l
o
g
[
A
g
+
]
2
[
C
u
2
+
]
=
+
0.474
+
0.059
2
l
o
g
(
0.1
)
2
1
=
0.415
V
The decrease in Gibbs energy
=
−
Δ
G
=
n
E
F
=
2
×
0.415
×
96500
=
80095
J
=
80.1
k
J
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0
Similar questions
Q.
We have cell
C
u
/
C
u
2
+
/
/
A
g
+
/
A
g
Reactions are given as below
C
u
2
+
+
e
→
C
u
+
E
1
∘
=
0.15
V
C
u
+
+
e
→
C
u
E
2
∘
=
0.5
V
A
g
+
+
e
→
A
g
E
3
∘
=
0.799
V
Calculate Gibbs free Energy.
Q.
The EMF of the following cells are:
C
u
|
C
u
2
+
(
1
M
)
|
|
A
g
+
(
1
M
)
|
A
g
,
E
0
=
0.46
V
Z
n
|
Z
n
2
+
(
1
M
)
|
|
C
u
2
+
(
1
M
)
|
C
u
,
E
0
=
1.10
V
The EMF of the cell
Z
n
|
Z
n
2
+
(
1
M
)
|
|
A
g
+
(
1
M
)
|
A
g
will be:
Q.
The EMFs of the following cells are
C
u
|
C
u
2
+
(
1
M
)
|
|
A
g
+
(
1
M
)
|
A
g
,
E
o
=
0.46
V
Z
n
|
Z
n
2
+
(
1
M
)
|
|
C
u
2
+
(
1
M
)
|
C
u
,
E
o
=
1.10
V
The EMF of the cell
Z
n
|
Z
n
2
+
|
|
A
g
+
(
1
M
)
|
A
g
will be:
Q.
Find the change in standard gibb's free energy
(
Δ
G
∘
)
for the following reaction.
2
C
u
+
→
C
u
+
C
u
2
+
(Given :
E
∘
C
u
+
/
C
u
=
0.52
V
,
E
∘
C
u
2
+
/
C
u
+
=
0.16
V
)
Q.
The emf
(
E
∘
)
of the following cells are:
A
g
/
A
g
+
(
1
M
)
∥
C
u
2
+
(
1
M
)
|
C
u
;
E
∘
=
−
0.46
v
o
l
t
Z
n
/
Z
n
2
+
(
1
M
)
∥
C
u
2
+
(
1
M
)
|
C
u
;
E
∘
=
+
1.10
v
o
l
t
Calculate the emf of the cell:
Z
n
|
Z
n
2
+
(
1
M
)
∥
A
g
+
(
1
M
)
|
A
g
.
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