Question

The total concentration of dissolved particles inside red blood cells is approximately $0.40M$, and the membrane surrounding the cells is semipermeable. What would be the osmotic pressure (in the atmosphere) inside the cells become if the cells were removed from the blood plasma and placed in pure water at $298K$?

• A. $9.79\text{atm}$
• B. $1.78\text{atm}$
• C. $2.34\text{atm}$
• D. $0.74\text{atm}$

Answer 1

The correct option is A $9.79\text{atm}$

Concentration of Red blood cell; $C=0.40M$
$R=0.0821{\text{L atm K}}^{-1}{\text{mol}}^{-1}$
$T=298K$
Osmotic pressure,${\pi }_i=CRT=0.40\times 0.0821\times 298$
$=9.786=9.79\text{atm}.$
Therefore, the correct answer is (a).