Question

The total kinetic energy of $8$ litres of helium molecules at $5$ atmosphere pressure will be
($1$ atmosphere = ${1.013\times 10}^5$pascal)

• A. $\text{607 J}$
• B. $\text{6078 J}$
• C. $\text{607 erg}$
• D. $\text{6078 erg}$

Answer 1

Answer: (B)

$\text{6078 J}$

$Given:$ The total K.E of 8 litres of helium molecules at 5 atmosphere pressure. ($1atmosphere=1.013\times {10}^{5}pascal)$

$Solution:$ We know that,

$E_k=\frac{3}{2}PV$

$=\frac{3}{2}\times 5\times 8\times 1.013\times {10}^5=60.78\times {10}^5=6078J$

$So,the$ $correct$ $option:B$