Question

The total number of atoms present in a molecule of cupric sulfate pentahydrate_____

Answer 1

The chemical formula for cupric sulfate

• The chemical symbol of the cupric ion is ${\mathrm{Cu}}^{+2}$
• The chemical symbol of sulfate ion is ${\left({\mathrm{SO}}_4\right)}^{-2}$
• Both ions combine together in a way such that

$$\begin{gathered} {\mathrm{Cu}}^{+2}{\left({\mathrm{SO}}_4\right)}^{-2} \\ 22(\mathrm{valency}\mathrm{is}\mathrm{cross}\mathrm{multiplied}\mathrm{to}\mathrm{get}\mathrm{the}\mathrm{compound}) \\ {\mathrm{Cu}}_2({\mathrm{SO}}_4{)}_2(\mathrm{simplifying}\mathrm{the}\mathrm{ratio}\mathrm{of}\mathrm{ions}) \\ {\mathrm{CuSO}}_4 \end{gathered}$$

The chemical formula for cupric sulfate pentahydrate is:

• The hydrate molecule of cupric sulfate is cupric sulfate pentahydrate. it contains 10 molecules of water for crystallization, hence the formula becomes:

${\mathrm{CuSO}}_4.10{\mathrm{H}}_2\mathrm{O}$

In cupric sulfate Pentahydrate, we have $1\mathrm{Cu}$ atom,$1\mathrm{S}$ atom, $14\mathrm{O}$ atom, and $20$ hydrogen atoms. so 36 atoms are present in the molecule.

Conclusion: The total number of atoms present in a molecule of cupric sulfate pentahydrate is 36