The total number of cells present after 'N' divisions of 'C' number of dividing cells will be

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C (N+1)

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C (N-1)

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C+N

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Solution

The correct option is B C (N+1)
In arithmetic growth, total number of cells after 'N' division of C number of cells = Number of initial cells ×(N+1) = C (N+1), where 'C' is the initial number of dividing cells.

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The total number of cells present after 'N' divisions of 'C' number of dividing cells will be

The correct option is B C (N+1)In arithmetic growth, total number of cells after 'N' division of C number of cells = Number of initial cells ×(N+1) = C (N+1), where 'C' is the initial number of dividing cells.

The correct option is B C (N+1)
In arithmetic growth, total number of cells after 'N' division of C number of cells = Number of initial cells ×(N+1) = C (N+1), where 'C' is the initial number of dividing cells.