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Question

The total number of distinct xR for which ∣ ∣ ∣xx21+x32x4x21+8x33x9x21+27x3∣ ∣ ∣=10 is

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Solution

∣ ∣ ∣xx21+x32x4x21+8x33x9x21+27x3∣ ∣ ∣=10
x3∣ ∣111241391∣ ∣+x6∣ ∣1112483927∣ ∣=10
R3R3R2
C3C3C2
R2R2R1
C2C2C1
x3∣ ∣111130150∣ ∣+x6∣ ∣1002243618∣ ∣
2x6+2x310=0
6x6+x35=0
(x3+1)(6x35)=0

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