CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

The total number of divisors of the form 4n+2(n0) of integer 240 is

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4
240=24×3×5
4n+2=2(2n+1)=2×odd
the required number of divisors
= the number of selections of one 2 from four 2s, any number of 3s from one 3 and any number of 5s from one 5.
=1×(1+1)×(1+1)=1×2×2=4

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image