MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Geometrical Isomerism in Octahedral Geometry

The total num...

Question

The total number of geometrical isomers possible for an octahedral complex of the type $[M A_{2} B_{2} C_{2}]$ is:
[ $M =$ transition metal; $A, B$ and $C$ are monodentate ligands]

A

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $5$

Suggest Corrections

thumbs-up

0

Similar questions

Q. In case of the octahedral complex of the type

[M (A A) a_{2} b c]^{n \pm}

, possible number of geometrical isomer(s) is/are:
Here
AA is a symmetrical bidentate ligand
a,b,c are monodentate ligands

Q. Octahedral complexes of the type

[M a_{2} b_{2} c_{2}]^{n \pm}

a, b, c

are monodentate ligands

Q. For the square planar complex,

[M (a) (b) (c) (d)]

=

central metal and a, b, c and d are monodentate ligands), the number of possible geometrical isomers are:

Q. For the square planar complex [Mabcd] where M is the central atom and a,b,c,d are monodentate ligands, the number of possible geometrical isomers are:

Q. For an octahedral complex

M X_{4} Y_{2}

(M = a transition metal , X and Y are monodentate achrial ligands), the correct statement, among the following is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Geometrical Isomerism in Octahedral Geometry

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Geometrical Isomerism in Octahedral Geometry

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon