Question

The total number of lone pair present in the molecule $Xe{F}_4$ is:

• A. 10
• B. 12
• C. 14
• D. 16

Answer 1

The correct option is C 14

Structure of $Xe{F}_4$ is:

Two lone pairs are present on the central atom $Xe$, while $3$ lone pairs are present on each of the $F$ atom.
So, a total of 14 lone pairs are present in the given compound.