The total number of optically active isomers for $C H_{2} O H (C H O H)_{3} C H O$ are:

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Solution

The correct option is C 8
There are three stereo centers.
So, optically active isomers $= 2^{3}$
$= 8$

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The total number of optically active isomers for $C H_{2} O H (C H O H)_{3} C H O$ are:

{C H}_{2} O H {(C H O H)}_{3} C H O

{C H}_{3} C H B r C H B r C O O H

C H_{3} C H (O H) C O O H

2, 3 -

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