The total number of possible isomers for $P t (N H_{3})_{4} C l_{2} B r_{2}$ is:

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Solution

$P t (N H_{3})_{4} C l_{2} B r_{2}$ exhibits ionisation isomerism. Each isomer exists in two structural forms i.e. cis and trans.
Possible structural isomers are:

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The total number of geometrical isomers possible for $[M (H O {(C H_{2})}_{2} N H_{2})_{2} {B r}_{2}]$ is:

C_{4} H_{6}

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