The total number of protons, electrons and neutrons in 12 g of $_{6}^{12} C$ is

1.084 \times 10^{25}

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6.022 \times 10^{23}

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6.022 \times 10^{22}

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Solution

The correct option is A $1.084 \times 10^{25}$
$_{6} C^{12}$ contains $6 N_{A}$ protons, $6 N_{A}$ and electrons $6 N_{A}$ neutrons. Total number of particles
$= 18 N_{A}$
$= 18 \times 6.023 \times 10^{23}$
$= 1.08 \times 10^{25}$

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Similar questions

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

Q. Total number of protons electrons and neutrons in 12 gram of

^{12} C_{6}

is:

Question 9
3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are
(a) $6.68 \times 10^{23}$
(b) $6.09 \times 10^{22}$
(c) $6.022 \times 10^{23}$
(d) $6.022 \times 10^{21}$

The number of electrons present in 60 g water is

If Avogadro's number is $6 \times 10^{23}$ , then the number of protons, neutrons and electrons in 14 g of $_{6} C^{14}$ are respectively:

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The total number of protons, electrons and neutrons in 12 g of 126C is

The correct option is A 1.084×10256C12 contains 6NA protons, 6NA and electrons 6NA neutrons. Total number of particles=18NA=18×6.023×1023=1.08×1025

The total number of protons, electrons and neutrons in 12 g of $_{6}^{12} C$ is

The correct option is A $1.084 \times 10^{25}$
$_{6} C^{12}$ contains $6 N_{A}$ protons, $6 N_{A}$ and electrons $6 N_{A}$ neutrons. Total number of particles
$= 18 N_{A}$
$= 18 \times 6.023 \times 10^{23}$
$= 1.08 \times 10^{25}$