Question

The total number of protons, electrons and neutrons in 12 g of ${}_6^{12}C$ is:

• A. $1.084\times {10}^{25}$
• B. $6.022\times {10}^{23}$
• C. $6.022\times {10}^{22}$
• D. $18$

Answer 1

Answer: (A)

$1.084\times {10}^{25}$

no. of moles of ${}_6^{1L}C$ atom in 12g=1mole.

$\therefore$ No. of Electron $=6.022\times {10}^{23}\times 6$

No. of Proton $=6.022\times {10}^{23}\times 6$

and No. of Neutron $=6.022\times {10}^{23}\times 6$

$\therefore$ Total no. of electron,proton and neutron $=6.022\times {10}^{23}(6+6+6)$

$\Rightarrow 18\times 6.022\times {10}^{23}$

$\Rightarrow 108.396\times {10}^{23}$ or $1.08396\times {10}^{25}$

Hence, the correct option is $\text{A}$